Экспоненциальный backoff

1async function retryWithBackoff(
2  fn: () => Promise<void>,
3  baseMs = 200,
4  maxAttempts = 5,
5): Promise<void> {
6  const jitter = () => 0.5 + Math.random() * 0.5 // 50–100%
7 
8  for (let attempt = 1; attempt <= maxAttempts; attempt++) {
9    try {
10      await fn()
11      return
12    } catch (e) {
13      if (attempt === maxAttempts) throw e
14      const delay = baseMs * 2 ** (attempt - 1) * jitter()
15      await new Promise((r) => setTimeout(r, delay))
16    }
17  }
18}